4x^2-100=4(x-5)(x+5)

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Solution for 4x^2-100=4(x-5)(x+5) equation: 


Simplifying
4x2 + -100 = 4(x + -5)(x + 5)

Reorder the terms:
-100 + 4x2 = 4(x + -5)(x + 5)

Reorder the terms:
-100 + 4x2 = 4(-5 + x)(x + 5)

Reorder the terms:
-100 + 4x2 = 4(-5 + x)(5 + x)

Multiply (-5 + x) * (5 + x)
-100 + 4x2 = 4(-5(5 + x) + x(5 + x))
-100 + 4x2 = 4((5 * -5 + x * -5) + x(5 + x))
-100 + 4x2 = 4((-25 + -5x) + x(5 + x))
-100 + 4x2 = 4(-25 + -5x + (5 * x + x * x))
-100 + 4x2 = 4(-25 + -5x + (5x + x2))

Combine like terms: -5x + 5x = 0
-100 + 4x2 = 4(-25 + 0 + x2)
-100 + 4x2 = 4(-25 + x2)
-100 + 4x2 = (-25 * 4 + x2 * 4)
-100 + 4x2 = (-100 + 4x2)

Add '100' to each side of the equation.
-100 + 100 + 4x2 = -100 + 100 + 4x2

Combine like terms: -100 + 100 = 0
0 + 4x2 = -100 + 100 + 4x2
4x2 = -100 + 100 + 4x2

Combine like terms: -100 + 100 = 0
4x2 = 0 + 4x2
4x2 = 4x2

Add '-4x2' to each side of the equation.
4x2 + -4x2 = 4x2 + -4x2

Combine like terms: 4x2 + -4x2 = 0
0 = 4x2 + -4x2

Combine like terms: 4x2 + -4x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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